00:01
We are given that this rlc circuit has a resistance of 50 oms, a capacitance of 200 times 10 to the negative 6th power.
00:19
That's micro -farids.
00:22
An inductance of 0 .1 -20 henry.
00:34
And the resistance of the coil, r sub l.
00:46
I'm not sure i like that, but anyway, resistance of the coil is 20.
00:57
The rms voltage is 240.
01:06
The frequency is 60 hertz.
01:10
Well, that means that the angular frequency is 2 pi times 60, so that would be 120 pi radiance per second.
01:26
So initially we need to calculate the rms voltage across the resistor.
01:31
The equivalent resistance across both resistors is 70 oms, 50 plus 20.
01:45
So to solve a, first i'm going to write down that z is the square root of re, q squared plus x sub l minus x sub c but x sub l is omega l x x sub c is one over omega c squared um i rms is v rms over z and then that will give me the rms current.
02:29
So let me put this in the calculator, the square root of the equivalent resistance squared, which is 70, plus omega -l 120 pi 1 -2, minus 1 over omega -c, 120, high, 200 times 10 to the negative 6 power.
03:10
Don't forget to square it.
03:14
That gives me 77 oms.
03:24
So i take my voltage divided by that, 240, divided by the 77, 7, 3 .1 amps.
03:46
Let's go back to the question.
03:51
The rms voltage across the resistor.
03:56
So voltage across the resistor is going to be the current times the resistance, which is 50 oms.
04:14
So i'll take the current times, and that gives me 156 to two significant digits...