Question
Area lying in the first quadrant between the ellipse $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ and the straight line $\frac{x}{a}+\frac{y}{b}=1$ is(a) $\frac{\pi}{4} a b+\frac{1}{2} a b$(b) $\frac{a b}{2}(\pi-2)$(c) $\frac{a b}{4}(\pi+1)$(d) $\frac{a b}{4}(\pi-2)$
Step 1
The ellipse $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$ and the straight line $\frac{x}{a}+\frac{y}{b}=1$ intersect at the points $(a,0)$ and $(0,b)$ in the first quadrant. Show more…
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