If the length of latusrectum of ellipse $E_{1}: 4(x+y-1)^{2}+2(x-y+3)^{2}=8$
and $E_{2}: \frac{x^{2}}{p}+\frac{y^{2}}{p^{2}}=1,(0<p<1)$ are equal, then area of ellipse $E_{2}$, is
(a) $\frac{\pi}{2}$
(b) $\frac{\pi}{\sqrt{2}}$
(c) $\frac{\pi}{2 \sqrt{2}}$
(d) $\frac{\pi}{4}$