00:01
So in this way here we're going to be working through problem 50 from chapter 20, which says arsenic reacts with oxygen to form oxides that react with water in a manner analogous to that of the phosphorus oxides.
00:12
Right balanced chemical equations describing the reaction of arsenic with oxygen and the reaction of the resulting oxide with water.
00:19
So we know we have arsenic coming together with oxygen, as plus o2, and we're forming an arsenic oxide.
00:26
But we need to figure out the formula of the arsenic oxide.
00:30
So we know that arsenic, because of the column or 3 % in the periodic table, is going to want to form a plus 3 oxidation state, while oxygen is going to want to form a minus 2 oxidation state.
00:46
So we have minus 2 and plus 3.
00:48
The least common multiple of 2 and 3 is 6.
00:50
So we're going to need 3 of our negatively charged anion.
00:56
Three of our minus two charges and two of our plus three charges in order for this to be balanced.
01:01
So the formula for the arsenic oxide is as203, arsenic trioxide.
01:09
So how do we balance this? so just starting out, i can see that i have an odd number of oxygen atoms on the right and an even number on the left.
01:17
So i'm going to put a coefficient of two in front of my as203 to make that an even number.
01:22
So now i have six oxygen atoms on the right and just two on the left.
01:27
So i'm going to put a coefficient of three in front of my o2.
01:30
And now i have the same number of oxygen atoms on both sides of the equation.
01:35
So that's balanced.
01:36
But i have four arsenic atoms in my product and only one arsenic atom in my reactant...