00:01
In this problem, we're given a sample of material that's unknown.
00:04
We know that it is 0 .5 .00 kilograms.
00:11
And there's heat that is being put into this sample, and the heat's being put in at a rate of 10 .0 kilojoules per minute.
00:23
We're provided a graph, and the graph shows us that the sample goes from negative 5 degrees celsius to 10 degrees celsius in a time of one minute.
00:37
That's all the sample is solid, then the sample is going to melt, and it takes a time of 1 .5 minutes for the sample to melt.
00:50
That's the transition from solid to liquid.
00:55
And then after this happens, the sample goes from a temperature of 10 degrees celsius to 40, degrees celsius.
01:05
That again happens in a time of 1 .5 minutes.
01:11
We want to find the various constants that are associated with heating the sample in liquid phase, melting the sample, and heating the sample in solid phase.
01:22
So the specific heat of the sample hunt solid, we'll call this c s for c solid, is going to be equal to the rate we're putting heat in, so that's 10 .0 kilojoules per minute multiplied by how long we heated the sample for.
01:46
So that was one minute.
01:51
And we also need to multiply by how much it heated up by, divided by how much it weighed.
01:58
So that's going to be 15 degrees celsius divided by 0 .5 .00 kilograms.
02:11
Putting this all together, we'll find we have a specific heat of 1 .33 kilojoules per kilogram degrees celsius.
02:27
Or we could also express this in terms of joules as 1 .33 times 10 to the third joules per kilogram degree celsius.
02:41
That would be the specific heat, how much energy...