Question
As an ice skater begins a spin, his angular speed is $3.17 \mathrm{rad} / \mathrm{s}$. After pulling in his arms, his angular speed increases to $5.46 \mathrm{rad} / \mathrm{s} .$ Find the ratio of the skater's final moment of inertia to his initial moment of inertia.
Step 1
This can be written as: \[I_i \omega_i = I_f \omega_f\] where \(I_i\) is the initial moment of inertia, \(\omega_i\) is the initial angular speed, \(I_f\) is the final moment of inertia, and \(\omega_f\) is the final angular speed. Show more…
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