As in Example 1 in the text we have $R(r)=c_{3} r^{n}+c_{4} r^{-n}$. In order that the solution be bounded as $r \rightarrow \infty$ we must define $c_{3}=0 .$ Hence $$u(r, \theta)=A_{0}+\sum_{n=1}^{\infty} r^{-n}\left(A_{n} \cos n \theta+B_{n} \sin n \theta\right)$$ where $$\begin{array}{l}
A_{0}=\frac{1}{2 \pi} \int_{0}^{2 \pi} f(\theta) d \theta \\
A_{n}=\frac{c^{n}}{\pi} \int_{0}^{2 \pi} f(\theta) \cos n \theta d \theta \\
B_{n}=\frac{c^{n}}{\pi} \int_{0}^{2 \pi} f(\theta) \sin n \theta d \theta
\end{array}$$.