As $\mathrm{O}_{2}(l)$ is cooled at $1 \mathrm{atm},$ it freezes at 54.5 $\mathrm{K}$ to form solid I.
At a lower temperature, solid I rearranges to solid II, which has a different crystal structure. Thermal measurements show that $\Delta H$ for the $I \rightarrow$ II phase transition is $-743.1 \mathrm{J} / \mathrm{mol}$ , and $\Delta S$ for the same transition is $-17.0 \mathrm{J} / \mathrm{K} \cdot$ mol. At what temperature are solids I and II in equilibrium?