As the gas trapped in a cylinder with a movable piston cools, 1.34 kJ of work is done on the gas

step 1 Okay, so for this question, the first thing that we should do is convert the work in kilojoules

As the gas trapped in a cylinder with a movable piston...

As the gas trapped in a cylinder with a movable piston cools, $1.34 \mathrm{kJ}$ of work is done on the gas by the surroundings. If the gas is at a constant pressure of $1.33 \times 10^{5} \mathrm{Pa}$, what is the change of volume (in L) of the gas?

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Key Concepts

Constant Pressure Process

In thermodynamics, a constant pressure process is one where the pressure remains unchanged while other state variables, such as volume, may vary. This concept is important because it allows the use of simplified relationships, like W = P?V, to relate the work done by or on the gas to the change in its volume.

Pressure-Volume Work

Pressure-volume work refers to the work performed when the volume of a gas changes under an external pressure. It is calculated using the formula W = P?V for processes occurring at constant pressure, linking the mechanical work to the energy transfer in thermodynamic systems.

Sign Conventions in Thermodynamics

Understanding sign conventions is crucial for correctly interpreting energy transfers. In thermodynamics, work done by the system is considered positive, while work done on the system is considered negative. This distinction helps in determining whether a system is doing work on its surroundings or having work done on it.

Unit Conversions

Unit conversion is a key concept in solving physics problems, ensuring consistency in the units used across calculations. Converting energy units from kilojoules to joules or volume from cubic meters to liters is necessary to accurately apply formulas and compare quantities within a problem.

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