Question
Assertion: Speed of a particle and magnitude of its acceleration in its SHM (time period $2 \pi$ second) are equal when its displacement from mean position is $\frac{A}{\sqrt{2}}$, where $A$ is amplitude of SHM. Reason: Speed of particle is maximum when acceleration of particle is zero.(A) $\mathrm{A}$(B) B(C) $\mathrm{C}$(D) D
Step 1
In SHM, the displacement of the particle is given by $x(t) = A\sin(\omega t)$, where $A$ is the amplitude, $\omega$ is the angular frequency, and $t$ is time. Show more…
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