00:01
Question 35 is asking us to compare the angular resolution of a one meter telescope when it observes in the near -infrared and when it observes in the violet region of the spectrum.
00:13
So to figure out a telescope's angular resolution, we need to use this formula.
00:23
Theta, meaning our angular resolution, is equal to 2 .06 times...
00:31
10 to the fifth times lambda over d in arc seconds.
00:45
Now for our problem, we know the values for lambda and we know the values for d, but the values for lambda change in this problem.
01:01
We know that our d is equal to 1 meter.
01:06
But our lambda is measured at 1 ,000 nanometers for the first part, and it's measured at 400 nanometers in the second.
01:28
Now to keep our units consistent, we're going to need to convert these nanometer wavelengths into meters.
01:35
1 nanometer is equal to 1 times 10 to the minus 9th meters.
01:41
So doing the unit conversions, we find that 1 ,000 meters is nanometers is equal to 1 times 10 to the negative 6th meters.
01:58
And 400 nanometers is equal to 4 times 10 to the negative 0...