00:02
In this problem, we're given a telescope with an aperture capital d that is one meter, and we need to find out the theoretical resolution or theoretical angular resolution when we are observing with first in the infrared region where the wavelength is about 1 ,000 nanometers.
00:32
Now we can convert the nanometers into the si units of meters, by multiplying it by the prefix nano, that is equal to 10 to the negative 9 meters, and that will give us the wavelength as 10 to the negative 6 meters.
00:53
And from there, we can just use the formula for angular resolution, theta, that is equal to 1 .22 times lambda divided by t.
01:06
Now, 1 .22 will come as it is, and we're going to substitute lambda equals 10 to the negative 6 meters, and d as 1.
01:20
And that gives theta is equal to 1 .22 into 10 to the negative 6 meters, and that is the theoretical resolution for the near infrared region.
01:37
Now for the next part, we're required to find out the angular resolution when we're observing using the same telescope in the violet region.
01:48
So that's 400 nanometers, the wavelength, and we're going to convert that into meters using the same procedure.
02:01
So that's 400 into 10 to the negative 9 to compensate for the prefix nano...