00:01
So this question asks, assuming a hardy -weimberg equilibrium, 21 % of a population is homozygous dominant, 50 % is heterogeneous, and 29 % is homozygous recessive.
00:12
So that's what percentage of the next generation is predicted to be homozygous recessive? so the equation for hardy -winberg is p -squared plus 2 p -2 plus q -squared is equal to 1.
00:30
So p is the frequency of the dominant oil, q is the frequency of the recessive allele, and p squared would be the frequency of the phenotype.
00:45
Q squared would be the frequency of the recessive phenotype, and 2pq would be the frequency of the heterozygote.
00:53
So 21 % is homozygous dominant.
00:57
So p squared, which is the frequency of the homozygous dominant phenotype is 0 .21.
01:13
50 % is heterozygous.
01:16
2 pq is equal to 0 .5.
01:24
And finally, 29 % is homozygous recessive.
01:29
So q squared is equal to 0 .29.
01:34
And if we can see, this all adds up to one...