Assuming an ideal diode, sketch vi, vd, and id for the half-wave rectifier of Fig. 168 . The inp

Assuming an ideal diode, sketch vi, vd, and id for the...

Key Concepts

Waveform Analysis

Waveform analysis in this context entails sketching the input sinusoidal voltage as well as the resulting output voltage and diode current. The process demonstrates that, when the diode is forward-biased, the output voltage mirrors the positive half-cycle of the input sine wave, while during the negative half-cycle the diode does not conduct, leading to a zero voltage and current. This analysis is crucial to understand the dynamic performance of the rectifier circuit.

DC Component Determination

The DC component of a rectified signal is the average or constant value present in the output waveform. For a half-wave rectified signal, this is obtained by averaging the output over one full period, typically involving integration of the positive portion of the sine wave and normalizing it by the period. This DC level is fundamental in applications where a steady voltage is required, and its calculation is a key aspect of power supply design.

Ideal Diode

An ideal diode is a theoretical electronic component that conducts current perfectly in one direction with zero voltage drop during conduction and completely blocks current in the reverse direction. This simplification aids in the analysis of circuits by eliminating complications due to forward voltage drop or reverse leakage, allowing clear insight into circuit behavior.

Half-Wave Rectification

Half-wave rectification is a process in power electronics where an alternating current (AC) input is converted into a pulsating direct current (DC) by allowing current to pass through the circuit only during one half-cycle (either positive or negative) and blocking the other half. This results in an output that consists of periodic pulses corresponding to the conducting half-cycles and zeros during the non-conducting periods.

Transcript

00:01 In this problem, we're asked to sketch vi, vd, and id for half wave rectifier for the figure that i've drawn right here.

00:09 The input is a sinusoidal wave with the frequency of 60 hertz.

00:15 Okay, so let's figure this out.

00:22 Determine the profile of the given dc level.

00:25 Okay.

00:26 So let's figure this out.

00:27 For the first part, let's find our, i'm going to go to the next page, so i have room to graph it.

00:37 The half rectified zinicide oil.

00:40 Vdc is equal 0 .318 vm.

00:46 So vm will equal vdc divided by 3 .18.

00:54 0 .318.

01:00 Okay.

01:02 And we're given 2, so this will be 2 divided by 0 .318 equals 6 .289 volts.

01:14 So the input can be represented by vit equals v .m times the sine of 2 pi f t.

01:32 So this will be 6 .289 times 120 pi t.

01:44 That's two times my frequency.

01:47 And this will look like, okay, this is zero.

01:58 This will be 2, 246, 2, 4, 6.

02:25 And this will be 5, 10, 20, 30.

02:42 I did that wrong, 10, 20, 30, 40.

02:50 5, 10, 15, 20, 25, 30, 30, 30, 40.

02:54 Okay, this could be 5, 10, 15, 20, 25, 30, 30, 35, and 40.

03:03 So we're gonna have a zero here and a zero just in front of 10, and a zero right after 15, and a zero at 25, and a zero at closer to 35 and 30.

03:21 And then i'll be a little above six, just before five.

03:29 So this will end a little below six just right smack between 10 and 15 so it's going to look like this and then it's going to keep going like that i'm not very good at drying these so and this is very rough okay and then next oh oh i'm on another page here so i'm going to have to go back and start erasing a few sorry about that for b we're doing vd.

04:28 And that's going to be, this is a forward bias for positon's diode is forward bias for positive applied voltage.

04:59 It behaves and behaves as a short circuit according to the ideal model while turning off the application of a negative bias acting as an open circuit where vd equals vi voltage of diode...

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