00:01
This is an aperture, excuse me, problem.
00:04
So, x equals 1 .22 lambda l over d.
00:16
D at night, i'm going to rate d sub n, is 8 .0 millimeters.
00:32
X is, the separation distance, is 1 .8 meters.
00:50
So i just realized, as i read this more, that this is actually a limit of resolution problem.
00:58
So the wavelength, we're to assume, at 525 nanometers.
01:11
And we're going to try to distinguish two headlights.
01:15
So, x objects equals 1 .22 lambda l to the objects.
01:28
To write that there over d so how far away that would be l x object times d over 1 .22 lambda 1 .8 meters 8 .0 millimeters 1 .2 millimeters 1 .22 525 that's nanometers if i put three zeros after it.
02:18
Now it would be...
02:21
No, i'm going the wrong way.
02:25
Erase that.
02:30
I want to write this in millimeters...