00:02
Good day everyone.
00:04
So here for our solution.
00:08
So first thing that we were gonna do here is we have no information on process b.
00:14
So we will start with a process da which is adiabatic.
00:18
So we have pd is equals to 1400 times 10 divided by 15 raised to the power of 1 .66.
00:32
So pd is equals to 712 kpa.
00:37
At point b we have the temperature is td is equals to 712 times 10 raised to the power of 3 times 15 times 10 raised to the power of 3 divided by 2 .34 times 8 .3145 which is equals to 549 kelvin.
00:59
Now we look at the process cd.
01:02
Since we have pc is equals to 712 times 10 raised to the power of 3 times 15 divided by 24.
01:10
So we have equal to 445 kpa.
01:15
So in this part we have to obtain the volume at point b.
01:21
So bp is equals to 24 times 10 raised to the power of 3 times 549 divided by 720.
01:30
1 divided by 0 .66.
01:34
And this would be equal to 15 .9 liters.
01:40
Now we need to find the pressure by using the equation.
01:44
That would be pp is equals to 2 .34 times 8 .3145 times 720 divided by 15 .9 times 10 raised to the power of negative 3...