Question

At $t=0^{-}$, just before the switch is opened, the current through the inductor in Figure P4.21 is $i_L=140 \mathrm{~mA}$. Is this value the same as that for DC steady-state? Was the circuit in steady state just before the switch was opened? Assume $V S= 10 \mathrm{~V}, R_1=1 \mathrm{k} \Omega, R_2=5 \mathrm{k} \Omega, R_3=2 \mathrm{k} \Omega$, and $L=1 \mathrm{mH}$. (FIGURE CAN'T COPY) Figure P4.21

   At $t=0^{-}$, just before the switch is opened, the current through the inductor in Figure P4.21 is $i_L=140 \mathrm{~mA}$. Is this value the same as that for DC steady-state? Was the circuit in steady state just before the switch was opened? Assume $V S= 10 \mathrm{~V}, R_1=1 \mathrm{k} \Omega, R_2=5 \mathrm{k} \Omega, R_3=2 \mathrm{k} \Omega$, and $L=1 \mathrm{mH}$.
(FIGURE CAN'T COPY)
Figure P4.21

Principles and Applications of Electrical Engineering

Giorgio Rizzoni,… 7th Edition

Chapter 4, Problem 21

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At $t=0^{-}$, just before the switch is opened, the current through the inductor in Figure P4.21 is $i_L=140 \mathrm{~mA}$. Is this value the same as that for DC steady-state? Was the circuit in steady state just before the switch was opened? Assume $V S= 10 \mathrm{~V}, R_1=1 \mathrm{k} \Omega, R_2=5 \mathrm{k} \Omega, R_3=2 \mathrm{k} \Omega$, and $L=1 \mathrm{mH}$. (FIGURE CAN'T COPY) Figure P4.21

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