00:01
In this question, we have a shaft and a plate that's rotating with an angular velocity of 14 radiance per second at this instance, an angular acceleration of 7 radiance per second square.
00:14
We need to determine the velocity and acceleration of point d, which is over here.
00:24
So first, we need to determine the direction of rotation.
00:29
Using our right hand rule, the direction or rotation will be along the position vector oa.
00:39
And from the question in given, from the diagram given the question, the position of the position of the oa is minus 0 .3i plus 0 .2j plus 0 .6k.
01:05
But we need the unit vector so i'm going to call it u hat it's going to be minus 0 .3i plus 0 .2j plus 0 .6k divide by the magnitude of the vector which is 0 .3 square plus 0 .2 square plus 0 .6 square sum square root and then simplify, you get 1 over 7 minus 3i plus 2j plus 6k.
01:41
So from here we can get our angular velocity vector, which is just the magnitude of angular velocity times the u head.
01:54
So this is 14 times 1 over 7 times the vector minus 3i plus 2 j plus 6k...