00:01
All right guys, to solve this problem, we first need to use the psychometric chart to determine the enthalpy h1, specific volume v1 and absolute humidity that is omega 1.
00:16
By using the given temperature, t1 is equal to 27 degrees centigrade.
00:22
And the relative humidity is 5 .1 is equal to 50%.
00:32
So h1 is equal to 55 .6 kilojoules per kg.
00:39
Then we have v1 is equal to 0 .87 cubic meter per kg.
00:47
Then we have omega 1 is equal to 0 .01115.
00:53
We can also determine the needed dew point temperature and wet bulb temperatures, that is temperature due point 1 is equal to 15 .7 degrees and temperature wet bulb 1 is equal to 19 .1 degrees.
01:14
Centigrade.
01:16
From the given volume of air that is two from the given volume of air that is the v is equal to two cubic meter and the number of changes that is n is equal to five per minutes and the specific volume we can calculate the mass flow rate of the air through the formula m is equal to v into n divided by v1.
01:50
So now we put the values over here and we get m is equal to two cubic meter into five per minutes divided by 0 .87 minutes, sorry, cubic meter per kg...