Atmospheric pressure is about $1.0 \times 10^{5} \mathrm{~Pa}$. How large a force does the still air in a room exert on the inside of a window pane that is $40 \mathrm{~cm} \times 80 \mathrm{~cm}$ ?
The atmosphere exerts a force normal to any surface placed in it. Consequently, the force on the window pane is perpendicular to the pane and is given by
$$F=P A=\left(1.0 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}\right)\left(0.40 \times 0.80 \mathrm{~m}^{2}\right)=3.2 \times 10^{4} \mathrm{~N}$$
Of course, a nearly equal force due to the atmosphere on the outside keeps the window from breaking.