00:01
In this exercise, we're going to talk about the dabbily wavelength.
00:03
So remember that according to the debrally formula, the momentum p of any particle is equal to punk's constant age divided by the wavelength of the particle, lambda.
00:16
And under the assumption that the particle is both massive and non -relativistic, the momentum can be written as the mass times the velocity, meaning that lambda is equal to h divided by mv.
00:32
This is the equation we have to keep in mind.
00:38
So in question a, we have to calculate what is the speed of an electron.
00:44
Remember that an electron has a mass of 9 .1 times 10 to the minus 31 kilograms.
00:55
And this electron has the wavelength.
01:02
Of 0 .2 nanometers.
01:06
So again, we have to calculate the speed v.
01:10
So i'm going to take that equation, so we have a lambda is equal to h over mv.
01:16
And from here, we obtain that v is h over m lambda.
01:21
So this is 6 .63 times 10 to the minus 34 joules second.
01:30
Then we have to divide it, divided by, 9 .1 times 10 to the minus 31 kilograms times lambda, that's 2 times 10 to the minus 10 meters...