Balance the following equations: (a) Cr(s)+Cl2(g) →CrCl3(s)...

Balance the following equations: (a) $\mathrm{Cr}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{g}) \rightarrow \mathrm{CrCl}_{3}(\mathrm{s})$ (b) $\mathrm{SiO}_{2}(\mathrm{s})+\mathrm{C}(\mathrm{s}) \rightarrow \mathrm{Si}(\mathrm{s})+\mathrm{CO}(\mathrm{g})$ (c) $\mathrm{Fe}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightarrow \mathrm{Fe}_{3} \mathrm{O}_{4}(\mathrm{s})+\mathrm{H}_{2}(\mathrm{g})$

Balance the following equations:
(a) $\mathrm{Cr}(\mathrm{s})+\mathrm{Cl}_{2}(\mathrm{g}) \rightarrow \mathrm{CrCl}_{3}(\mathrm{s})$
(b) $\mathrm{SiO}_{2}(\mathrm{s})+\mathrm{C}(\mathrm{s}) \rightarrow \mathrm{Si}(\mathrm{s})+\mathrm{CO}(\mathrm{g})$
(c) $\mathrm{Fe}(\mathrm{s})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g}) \rightarrow \mathrm{Fe}_{3} \mathrm{O}_{4}(\mathrm{s})+\mathrm{H}_{2}(\mathrm{g})$

Key Concepts

Balancing Chemical Equations

Balancing chemical equations is a technique used to satisfy the law of conservation of mass. This involves adjusting the coefficients of reactants and products to ensure that the number of atoms for each element is equal on both sides of the equation, without changing the formulas of the substances involved.

Chemical Equations

Chemical equations are symbolic representations of chemical reactions where the reactants are transformed into products. They use chemical formulas to denote substances and are structured to show the reactants on the left, an arrow indicating the transformation, and the products on the right.

Law of Conservation of Mass

The law of conservation of mass states that matter is neither created nor destroyed during a chemical reaction. This principle requires that the total number of atoms for each element in the reactants must equal the total number of atoms for each element in the products, which is the basis for balancing chemical equations.

Stoichiometry

Stoichiometry is the quantitative relationship between reactants and products in a chemical reaction. It involves calculating the amounts of substances involved and ensuring that the coefficients in a balanced equation correctly reflect the conservation of atoms and mass.

Transcript

00:01 Hello, friends.

00:01 In this video, we will learn about how to balance the chemical equation, so we'll take a few examples.

00:08 Our first example.

00:09 Iss balancing a chemical equation for reaction between chromium would just see our it reacts with chlorine, which is c l two to give chromium flow right, which is c r c l tree.

00:29 So let's make a note of the number off atoms off the different elements on both the sides so we can write your react inside and brought upside.

00:48 So let's make a lot off it.

00:49 So the number off chromium atoms on the weapon silas one on the hotel is one as well on the wrecked inside.

00:58 The number off chlorine happens is to the number of chlorine atoms on the worksite.

01:04 This tree, right, so always remember the rule.

01:07 First, you have to balance the mac labs 1st 1st always battle balance the metal atoms than the normal than oxygen, then hydrogen.

01:23 Okay, so we can see here the crew me, mr metal act, right.

01:27 So let's see, so chromium atoms are only balance or it's like only one atom.

01:31 A move the sites.

01:32 Now let's try to balance the chlorine atoms so we can see chlorine atoms.

01:37 There are two outcomes on the reactant side and then three atoms on the prep site.

01:42 So let's try to make get of common number.

01:45 So in getting put a three here, it becomes six chlorine atoms, right? and then, to make this the number of carbon atoms, also six we need to put up through here.

02:06 Right? so the common my people off to 136 okay, so that we can work it out.

02:16 So this becomes six.

02:17 So the number of chlorine atoms onboard the sites becomes six now, so let's now.

02:23 So because of this change, the chromium number that comes off chromium have become too on the correct side.

02:32 So we can make the number off chromium atoms to as valerie actor in sight so we can put it to here.

02:39 And our equation ist balance now.

02:41 So on both the sites are the number of chromium atoms are two on the number of chlorine atoms are six, right? so two atoms of chromium react with three molecules of chlorine gas to give two molecules off chromium plowright hope you understand.

02:58 We will take one more example now okay, so in this example, we have silicon dioxide, which is as i 02 reacting with carbon to give silicon and carbon monoxide.

03:13 So let's make a note off the number of atoms off different elements on both the sides.

03:19 So react inside and product site.

03:27 Okay, so we've only seen that first, we need to balance the metal atoms than the long matt latin's, their oxygen and then high protein.

03:36 So we can see here.

03:37 There are no metal atoms.

03:39 We have silicone, we have carbon.

03:43 And then the oxygen.

03:45 Right.

03:45 So let's make a north off the number of atoms off these on both the sides.

03:50 So silicon is one on each side.

03:52 Carbon is one on each side, and then we have oxygen, which is to on the reactor inside and only one on the product side.

04:03 Right? so so since silicon and carbon there already balanced, let's look up to oxygen.

04:10 How? louis balance it...

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