00:01
Okay, so we are given with tension on ab, which is this, and tension on bc, which is this, okay, rope.
00:09
And we need to find that moment about o, that is origin, for the resultant force acting at point b.
00:19
Okay, so let's start by finding the vector forces acting on point b.
00:26
Okay, so first we need the distance a, b.
00:28
So that can be calculated distance ab is equals to we know the coordinates of point a so point a in x direction it is minus 0 .75 in y direction it is zero and in z direction it is 0 and in z direction it is 6 meters right and point c can be written in x direction it is 4 .25 in y direction it is 0 and in z direction it is you can see here this value which is 1 meter and point b is x direction is 0 and z sorry y direction is 7 this one and z direction is 0 so well applying that formula what is distance from x2 minus x1 so that gives minus 0 .75 square for d ab so here minus 0 .75 minus 0.
01:31
Next will be 0 minus 7, so that is minus 7 square and 6 minus 0, which is 6 square.
01:40
So on calculating this, we get 9 .25 meters.
01:45
Similarly, distance bc is equals to root of 4 .25 minus 0, so 4 .25 square, 0 minus 7, so minus 7 square, and 1 minus 0, so 1 square.
02:02
And this gives us 8 .25 meters.
02:06
So now we have distance.
02:07
So now we can calculate tension b .a.
02:11
That is tension acting at b, okay, in a direction, or ba direction, sorry.
02:20
So that is equal to tension ba times vector ba over magnitude of ba, which is distance ba.
02:31
So this is equals to 55 as given.
02:35
This is 9 .25.
02:38
And vector b .a is minus 0 .5, right? so b .a.
02:45
Minus 0 .75.
02:47
I, then minus 7j.
02:51
Right...