Question
$$\begin{aligned}&\begin{aligned}&\hline\end{aligned}\\&\int \sec ^{4} 3 \theta d \theta[\text { Hint: Apply a trigonometric identity.] }\end{aligned}$$
Step 1
This allows us to rewrite the integral as follows: $$ \int \sec^4 3\theta d\theta = \int (\sec^2 3\theta)^2 d\theta = \int (1 + \tan^2 3\theta)^2 d\theta $$ Show more…
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