00:01
Hi, in this problem, we are given some of the compounds where we have to find out the oxidation number of carbon in each of the given compounds.
00:11
So let the oxidation number of carbon in each compound is x.
00:26
Now we know that all these compounds are neutral and in a neutral compound, the sum of the oxidation numbers of all the elements is equals to zero.
00:35
So oxidation number for hydrogen is plus one for oxygen it is minus two.
00:42
Calculating for carbon, we can write x plus three times one plus minus two plus one equals to zero.
00:59
Calculating the value of x, we get the value of x as minus two.
01:05
So the oxidation number of carbon in ch3 oh is minus 2.
01:11
Moving on to the next compound, we have ch2o oxidation number of oxygen is minus 2 for hydrogen.
01:17
It is plus 1.
01:19
So following the same way, we can let x plus 2 times 1 plus minus 2 equals to 0...