00:01
So let's first of all find the focal lens of both of those glasses.
00:06
So for bill, the near point is 125 centimeters, which would then mean that d .i would be equal to negative 125 minus 2 centimeters that he wears his glasses in front of the i.
00:24
So the di is negative 123 centimeters.
00:27
The d -o, the object, is at the 25 -centimeter distance.
00:35
So we can now find the focal length.
00:38
So 1 over f is equal to 1 over do plus 1 over d -i.
00:43
1 over 5 minus 1 over 23.
00:51
So that gives the focal length of bill's classes as 28 point.
00:58
Three centimeters.
01:00
So now the next thing we need is the focal length of anne's glasses.
01:06
So for ann, we know that her near point is at 75 .0 centimeters, which means that the i for her would be negative 75 minus two centimeters.
01:18
Two centimeters is the distance between her eyes and the glasses.
01:22
So that would be negative 73 centimeters.
01:25
So 1 over f would be equal to 1 over 25 minus 1 over 73 from the thin lens formula.
01:33
So the focal length of anne's glasses is equal to 33 .6 centimeters...