00:01
Bill is far -sighted and has a near point located 125 centimeters from its eyes.
00:07
Anne is also far -sighted, but her near point is 75 centimeters from her eyes.
00:11
Both have glasses that correct their vision to a normal near point, which is 25 centimeters, and both wear glasses two centimeters from their eyes.
00:20
Relative to the eyes, what is the closest object that can be seen clearly by anne who wears bill's glasses and by bill who wears anne's glasses.
00:32
So the formula that we need here is 1 over f is equal to 1 over do plus 1 over d .i.
00:42
So let's look at bill.
00:46
So the object's distance of bill is 25 minus 2 centimeters, which is 23 centimeters.
00:56
The image distance for bill is negative, 125 minus 2 centimeters, so negative, 1923 centimeters.
01:11
The object distance for ann is, again, 25 minus 2, which is 23 centimeters, and the image distance for ann is negative 75 minus 2, which is negative 73 centimeters.
01:30
Okay, so all of the distance, the image distance are negative because all of these images are going to be virtual images based on the type of lenses.
01:42
So we can rewrite this equation in terms of the focal lengths, which is one over d .i plus one over d .o.
01:54
The negative one power, that makes it a little bit easier to see what's happening.
01:58
So the focal point, in this case for bill, is equal to when we plug in values, 28 .3 centimeters.
02:10
Same thing for ann, same equation, but using ann's numbers.
02:16
The focal length is 33 .6 centimeters...