Boiling Water at High Pressure. When water is boiled at a pressure of $2.00 \mathrm{atm},$ the heat of vaporization is $2.20 \times 10^{5} \mathrm{J} / \mathrm{kg}$ and the boiling point is $120^{\circ} \mathrm{C}$ . At this pressure, 1.00 $\mathrm{kg}$ of water has a volume of $1.00 \times 10^{-3} \mathrm{m}^{3}$ , and 1.00 $\mathrm{kg}$ of steam has a volume of $0.824 \mathrm{m}^{3} .$ (a) Compute the work done when 1.00 $\mathrm{kg}$ of steam is formed at this temperature. (b) Compute the increase in internal energy of the water.