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In this video, we're going to look at inorganic benzene, which is this chemical formula.
00:09
And when we're looking at inorganic benzene, it actually is a ring cyclical for a rent, where we have benzene, will be alternate boron nitrogen, boron nitrogen, right, as such.
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And so it kind of makes this six hexagon type of shape, and i didn't do the best of drawing it.
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But anyways, we have, but it alternates boron nitrogen, boron nitrogen as we go around.
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Then we have a hydrogen that is bonded to each of these as such.
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And so what i want to do is i want to draw a lewis structure of this, placing the extra, what am i trying to say, the extra electrons.
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Needed on here.
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And so we're going to look at this really fast.
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So boron we know has, let me pull up my periodic table, three valence electrons.
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So we're going to take three and we're going to times that by three.
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We're going to add nitrogen that has five, so three times by five, plus our six electrons for each hydrogen.
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So let's solve for this.
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So we got three times three is nine plus 15, plus six.
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Now let's see.
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15 plus 9 would be 5 .24 plus 6 is going to be 30.
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Okay.
01:46
So we have our 30 total electrons.
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So let's see how many i've got on here so far.
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So 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 17, 18, 19, 20, 22.
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So i've got 22 electrons on there so far.
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So that leaves me with 8.
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I just want to verify that count those rights.
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1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12.
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1, 2, 3, 4, 5, 6, 7, 8, 9 10, 11, 12.
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No, i did not do that right.
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Now, these, no, 6.
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Let me count that one more time.
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I just want to make sure...