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Hello there.
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In this problem, we are asked to derive the equation for an ellipse.
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It's a challenge problem, so it's a little bit time -consuming.
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But we're going to start with what we know about a general eclipse, and then we're going to see how to get to the standard form equation for an ellipse.
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So we've got an ellipse with a fosy at c -coma -0 and minus c -coma -0.
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And the definition of an ellipse says that any point on that ellipse, the distance from one focus and the distance from the other focus added together is a constant value.
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And then the problem they said they want us to set that constant to 2a.
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And a, if you'll remember, is also half the length of the major axis.
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So that would be a distance there.
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So what i've gotten is a triangle drawn from the foci to a point on the ellipse and label.
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Those d1 and d2.
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So what we're saying is we want d1 plus d2 to be a constant to a.
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And that's just the definition of an ellipse.
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And so if i know that, then i can find what d1 and d2 are using the pythagorean theorem.
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If you remember that, a squared plus b squared equals c squared is a pythagorean theorem.
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So we're going to use that to fill in d1 and d2.
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So first, d1 is going to be square root of x minus c.
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That's x minus a negative c.
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So it's going to be x plus c squared plus y squared.
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Then we're going to add d2.
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D2 is going to be x minus c squared plus y squared.
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And that's going to equal to a.
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So that's our basic equation that just says that the distance d1 and d2 added together equals 2a.
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And from here, now we've got it set up, we're just going to do some, do a little bit algebra to solve this.
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So let's take this term and move it over to the other side.
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That's going to give us square root of x minus c squared plus y squared equals to 2a minus square of x plus c squared plus y squared.
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Okay, and now let's take that and we'll square both sides and we'll end up with x minus c squared, x minus c squared plus y squared on this side is equal to.
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Remember, we're going to square this entire expression and it's got that negative sign in there.
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So we're going to have to square the entire expression.
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We're going to end up with is 4a squared minus 4a square roots of x plus c squared plus y squared plus x plus c squared plus y squared.
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So now we have some common terms on both sides.
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So we can eliminate y squared from both sides.
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And then we can expand our expressions one more time.
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We can take this term and square it, this term and square it.
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So we have x squared minus 2xc plus c squared equals 4a squared minus 4a squared of x plus c squared, plus y squared plus x squared minus 2 x c plus c squared so now again we got some like terms on both sides we have an x squared that we can cancel out we have a c square that we can cancel out and then we can rewrite that expression so you keep your notes so i'm going to erase this stuff on the top i'll be able to do this in a faster way okay then we'll move that expression up to the top and we'll keep working.
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So really is just algebra, just keeping track of what we're doing and keeping everything organized.
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So coming back up to the top, we have minus 2xc remaining on that side equals 4a squared minus 4a times a square root of x plus c squared plus y squared and then minus 2xc...