00:01
Hi there, so for this problem we have an arrangement of capacitors as is shown in this figure.
00:07
Now we know that the capacitance 1 is equal to 10 microforats, the capacitance 2 is 20 microferrets, and the capacitance 3 is 25 microferrets.
00:30
Now, the problem is that no capacitor can withstand a potential difference that is more than 100 volts.
00:44
So what we need to find for the first part of this problem is what is the magnitude of the maximum potential difference that can exist between the points a and b.
00:59
So we need to find that potential difference.
01:03
Now, they each store the same charge because they are in series.
01:15
They have the same charge.
01:19
Now, so the maximum voltage is across the smaller capacitors.
01:28
So with 100 bolts across, we are going to have that.
01:33
The voltage of 1 is 100 volts because that is, the one with the smallest capacitance.
01:45
And the voltage across the 21, the 20 micro -farets, is going to be 50 volts because it has twice as the capacitance of the first one, and the voltage across the 25 microphrates capacitor is going to be 40.
02:11
40 volts.
02:15
So with this set, we can sum, we know that total voltage in here is the sum of all of this...