00:01
So in this question we have the standing wave function here this one, and we want to check if it's a solution for the wave equation, this one, if the speed of the wave is omega over t.
00:14
Now to start, we're going to find the spatial derivative, the first and second special derivative for this wave equation.
00:21
So partial y over partial x is equal to the amplitude times k sine or cosine because we took the derivative cosine kx sine omega t the second derivative partial y over partial x square the second derivative is a is w k square and here we'll add a negative sign because the derivative of cosine is negative sign, sine kx, sine omega t, which is equal to minus k square y.
01:10
Now we'll find the first and second time derivative for this wave equation or for this wave function.
01:18
So partial y over partial t is equal to a omega sine kx cosine cosine omega t and therefore the second derivative with respect to time is equal to negative omega square a is w, sine k x, sine omega t, which is just negative omega y.
01:57
Now we plug this into the wave equation to check if this wave function is a solution.
02:08
So we write the wave equation again partial y over partial x equal 1 over v squared...