00:01
Okay, so we're going to see, we can figure out when a precipitate first starts to form here.
00:05
Okay.
00:08
I think we probably want to start by writing our reaction.
00:13
Okay, so the cadmium hydroxide is going to be an in equilibrium with its ions.
00:20
So plus 2 .0 .h.
00:22
Minus.
00:23
Okay.
00:23
So our ksp expression is a concentration of cadmium ion times hydroxide ion.
00:33
Squared, okay? and we're trying to figure out the concentration of the cadmium ion, and they've given us information about the oh minus by giving us a ph.
00:43
So the ph is 9 .62.
00:46
So i'm going to subtract that from 14 and get the poh, which is 4 .38.
00:53
And then 10 to the negative 4 .38 will give us our oh -h minus.
00:58
So that's going to be 4 .17 times 10 of the negative 5 molar.
01:04
So i'm going to take the ksp expression now.
01:06
I know my ksp is 2 .5 times 10 of the negative 14...