00:01
So in this expression, what i have is after you drink a cup of coffee, you have 80 milligrams of caffeine, and then after tea hours is the amount of caffeine in your system.
00:10
So first, how long will it take for the amount of caffeine to drop below 60 milligrams? okay, so i want this to be less than 60.
00:17
So i need my caffeine to be 60 equals 80 -t negative zero.
00:24
T over six.
00:25
What do i do first? i want to get my t -term by itself, so i'm going to divide by 80 to both sides.
00:30
So 60 divided by 80, that's approximately 0 .75 or 3 fourths equals 2, negative t over 6.
00:38
How do i get rid of that 2? well, how do i get rid its exponent? what i could do is just take the natural log of both sides.
00:45
I could also take the log base 2, or i could take the natural log.
00:49
This will be ln of 0 .75.
00:52
Rules of logarithms bring down the negative t over 6 times ln of 2.
00:58
And then what i could do is multiply by the, i'm trying to get t by itself, so the reciprocal of this fraction 6 over negative l and of 2 to both sides, times 6 over negative l and of 2.
01:15
This cancels with the negative especially.
01:18
So t, if i were to plug this in my calculator times l &o 0 .75 divided by negative l and of 2.
01:26
How much time would it take? 2 .49 hour...