00:01
This problem allows us to practice our stoichiometry in order to compare the various amount of energy that is essentially used or emitted by alpha, beta, and gamma radiation, which is a critical piece of the understanding of nuclear chemistry.
00:19
Let's first note our conversion factor that we're given that we're going to be using this entire problem, which is one mega electron volt is equivalent to 1 .6 times 10 to the negative 13th joules.
00:34
This allows us to convert electron volts into another unit of energy.
00:40
For alpha radiation, we have a 5 mega electron volts, and we'll multiply that by the fact that in every one mega, mega electron volt, we have 1 .6 times 10 to the negative 13th joules.
00:54
So we'll get that in alpha radiation, our energy is 8 times 10 to the negative 13th joules.
01:02
On to beta radiation, we're given we have 1 mega electron volt.
01:09
We'll multiply that by the fact that again in every 1 mega electron volt, we have 1 .6 times 10 to the negative 13th joules and we'll get 1 .6 times 10 to the negative 13th joules...