This is done using the formula $Q_1 = m \cdot \Delta H_{fus}$, where $m$ is the mass of the ice and $\Delta H_{fus}$ is the heat of fusion of water. The heat of fusion of water is $334 \mathrm{~J/g}$, so we have:
\[Q_1 = 65.0 \mathrm{~g} \times 334 \mathrm{~J/g} =
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