We use the formula for latent heat, which is $Q = m \cdot L$, where $Q$ is the heat, $m$ is the mass, and $L$ is the latent heat of fusion. For ice, $L$ is 80 cal/g. So, we have:
\[Q = 80 \, \text{g} \times 80 \, \text{cal/g} = 6400 \, \text{cal}.\]
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