Question
Calculate the dc value of $I_C$ for the common collector amplifier in Figure P11.56 assuming the following values:$$\begin{aligned}& R_1=4 \mathrm{k} \Omega \\& R_2=2 \mathrm{k} \Omega \quad R_E=1.0 \mathrm{k} \Omega\end{aligned}$$Figure P11.56 can't copy
Step 1
The resistors \(R_1\) and \(R_2\) form a voltage divider. \[ V_{TH} = \frac{R_2}{R_1 + R_2} \cdot V_{CC} \] Assuming \(V_{CC}\) is provided (if not, we will denote it as \(V_{CC}\) for now). \[ R_{TH} = \frac{R_1 \cdot R_2}{R_1 + R_2} \] Show more…
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