00:09
Let's calculate the electronegativity difference for each and indicate which type of bond may be formed.
00:16
When we calculate the electronegativity difference, we see that difference of 0 to 0 .3 would yield a non -polar covalent bond.
00:32
And electronegativity difference of 0 .4 to 1 .7 would produce a polar covalent bond.
00:44
And the electronegativity difference of 1 .8 to 4 would produce an ionic bond.
00:54
For a, look at bond form between silicon and chlorine.
01:01
Now, the electronegativity table that i use might be slightly different here.
01:05
The electronegativity of silicon is 1 .8, and for chlorine is 2 .8.
01:10
The electronegativity difference here is 2 .8 minus 1 .8, which is 1 .0, and this would produce a polar covalent bond.
01:23
For b, carbon, carbon, electronegativity of carbon is 2 .5...