00:01
So in each example here, we're going to assume that we have 100 grams of our substance.
00:07
So then we can take our percentages and make them grams.
00:11
So 10 .4 grams of carbon, 27 .8 grams of sulfur and 61 .7 grams of chlorine.
00:22
Empirical formulas are ratios of moles, not grams.
00:26
So let's take a minute and change all of these grams to moles.
00:29
So carbon is 12 .01, sulfur is 32 .07, and chlorine is 35 .45.
00:47
So we've got our moles, 0 .866, 0 .867, and 1 .74.
00:59
So we get to a whole number ratio now.
01:02
We just take them all and divide them all by the smallest number.
01:07
So we'll divide all of these by 0 .866.
01:10
So our formula is c -s -c -c -l -2.
01:23
So our second example, we've got 21 .7 grams of carbon, 9 .6 grams of oxygen, and 68 .7 grams of fluorine.
01:39
Again, first step is to change grams to moles.
01:54
Carbons 12 .01, oxygen is 16...