00:18
Fe2 .03 reacts with carbon monoxide to give us iron and co2.
00:47
Delta h is negative 23 kilojoules.
00:56
I am going to multiply this equation by 3, and that will help me down the road.
01:05
So that gives a coefficient of 3, changes that to 6 iron, that to 9, co2, delta h is now negative 69.
01:18
Our next equation is iron 4 oxide, reacting with co2, to give us iron 3 oxide plus carbon monoxide.
01:56
And delta h is positive 39, but i switched this equation.
02:04
So originally the products were the reactants, and originally delta h was a negative.
02:13
At this point, i can cancel out a few things.
02:17
I can cancel out one of my co2s, so that leaves me with eight co2s up here.
02:25
I can cancel out one of my carbon monoxide.
02:28
That leaves me with two carbon monoxides here.
02:33
And i can cancel out the three fe2.
02:37
That's why i multiplied by 3 in the original equation.
02:44
So at this point, we've got fe 304 plus 2 co, yielding 6 iron, and 8 co2.
03:00
The next equation is 2fe 304 plus 8 coo, that gives us, i'm sorry, this is 2fe 304, plus 8 coo, that gives us, i'm sorry, this is this is what our current equation looks like after those original crossouts.
03:45
And so delta h here at this point is negative 39.
04:00
All right...