Question
Calculate the enthalpy change for the reaction$$\mathrm{P}_{4} \mathrm{O}_{6}(s)+2 \mathrm{O}_{2}(g) \stackrel{-\cdots}{\mathrm{P}}_{4} \mathrm{O}_{10}(s)$$given the following enthalpies of reaction:$$\begin{array}{ll}\mathrm{P}_{4}(\mathrm{~s})+3 \mathrm{O}_{2}(g)-\mathrm{r} \rightarrow \mathrm{P}_{4} \mathrm{O}_{6}(s) & \Delta H=-1640.1 \mathrm{~kJ} \\\mathrm{P}_{4}(s)+5 \mathrm{O}_{2}(g)-\cdots \mathrm{P}_{4} \mathrm{O}_{1} 0(s) & \Delta H=-2940.1 \mathrm{~kJ}\end{array}$$
Step 1
Step 1: First, we write down the reaction for which we want to find the enthalpy change: $$ \mathrm{P}_{4} \mathrm{O}_{6}(s)+2 \mathrm{O}_{2}(g) \rightarrow \mathrm{P}_{4} \mathrm{O}_{10}(s) $$ Show more…
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Calculate the enthalpy change for the reaction $$\mathrm{P}_{4} \mathrm{O}_{6}(s)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{P}_{4} \mathrm{O}_{10}(s)$$ given the following enthalpies of reaction: $$\begin{array}{ll}{\mathrm{P}_{4}(s)+3 \mathrm{O}_{2}(g) \longrightarrow \mathrm{P}_{4} \mathrm{O}_{6}(s)} & {\Delta H=-1640.1 \mathrm{kJ}} \\ {\mathrm{P}_{4}(s)+5 \mathrm{O}_{2}(g) \longrightarrow \mathrm{P}_{4} \mathrm{O}_{10}(s)} & {\Delta H=-2940.1 \mathrm{kJ}}\end{array}$$
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