Question
Calculate the equilibrium concentration of $\mathrm{Zn}^{2+}$ in a solution initially with 0.150 $\mathrm{M} \mathrm{Zn}^{2+}$ and 2.50 $\mathrm{MCN}$ .
Step 1
The reaction is $\mathrm{Zn(CN)_4^{2-}}$ dissociating into $\mathrm{Zn^{2+}}$ and $\mathrm{4CN^-}$. So, the reaction is: \[\mathrm{Zn(CN)_4^{2-}} \rightarrow \mathrm{Zn^{2+}} + 4\mathrm{CN^-}\] Show more…
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