00:01
We will use both newton's method and the second method to calculate root for the nonlinear equation sign of x equals 0.
00:10
As first guess for the newton's method, we got to use x0 equals 1.
00:16
And as the other guess to the second method, beside this x not equal 1, is we got to use the first guess from newton's method.
00:29
So we get to apply first the newton's method.
00:32
To obtain its first guess and use that value besides the value one as the first guesses for the second method.
00:47
Now here we know that the newton's method is given by xub n plus 1 equals x of n minus f of x of n divided by the derivative of f at x of n for n greater than equal to 0 and x x not given.
01:14
And for the second method, we have x sub n equals x of n minus 1 minus f of x of n minus 1 times a fraction whose numerator is x of n minus 1 minus 1 minus x of n minus 2 divided by f sub x sub n minus 1 minus f at x of n minus 2 and that for n very then are equal to 2 because we can we begin for you start calculating x2 from x0 and x1 which are given and then for the second method we only need the function f and for the newton's method we need the function f and its derivative.
02:23
And the function f, we know in this case, is equal to sine of x.
02:29
His derivative is cosine of x.
02:33
So these are the two functions we use in the newton's method.
02:37
And this is the function we got to use in the second method to write a computer program or an updating rule in a calculator...