00:01
In this problem, we are given a chemical reaction, and we are also told the values for the change in enthalpy delta h and the change in entropy delta s at standard conditions.
00:12
And we want to determine what the value is of the change in gibbs free energy delta g at standard conditions at a temperature of 25 degrees celsius, which correlates to 298 kelvin.
00:25
So we use this equation to directly solve for that value.
00:29
And then based on whatever the sign is of delta g, we can predict whether or not this reaction will proceed spontaneously.
00:38
So we have the values of delta h t and delta s.
00:42
So we can just plug those and solve for delta g at standard conditions.
00:47
We are told that delta h at standard conditions is negative 2 ,217 kilojoules.
00:53
We can convert that into joules by multiplying by 1 ,000...