Question
Calculate the half-life, in years, for the reaction $2 \mathrm{X} \rightarrow \mathrm{Y}$ when the starting concentration of $X$ is $6 \mu M$ and the rate constant is $3.6 \times$ $10^{-3} \mathrm{M}^{-1} \cdot \mathrm{s}^{-1}$
Step 1
Step 1: The half-life for a second order reaction is given by the formula $t_{1/2} = \frac{1}{k[A]_0}$, where $k$ is the rate constant and $[A]_0$ is the initial concentration of the reactant. Show more…
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Calculate the half-life, in years, for the reaction $2 X \rightarrow Y$ when the starting concentration of $X$ is 6 yeM and the rate constant is $3.6 \times 10^{-3} \mathrm{M}^{-1}\cdot 8^{-1}$.
Derive the expression that relates rate constant to the half-life. Hint: the concentration at this time (t1/2) is half the concentration with which you started. Substitute this information into the equation for a first-order reaction
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