Question
Calculate the magnitude of work done on the tool by $\vec{F}$. If this displacement is along the straight line $y=x$ that connects these two points.(A) $2.50 \mathrm{~J}$(B) $500 \mathrm{~J}$(C) $50.6 \mathrm{~J}$(D) $2 \mathrm{~J}$
Step 1
Step 1: The given force is $\vec{F} = -\alpha x y^2 \hat{j}$ and the displacement is along the line $y=x$. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate the work done on the tool by $\vec{F}$ of the tool is first moved out along the $x$-axis to the point $x=3.00 \mathrm{~m}, y=0$ and then moved parallel to the $y$-axis to $x=3.00 \mathrm{~m}, y=3.00 \mathrm{~m}$ (A) $67.5 \mathrm{~J}$ (B) $85 \mathrm{~J}$ (C) $102 \mathrm{~J}$ (D) $7.5 \mathrm{~J}$
Given below is a graph between a variable force (F) (along $\mathrm{y}$ -axis) and the displacement $(\mathrm{X})$ (along $\mathrm{x}$ -axis) of a particle in one dimension. The work done by the force in the displacement interval between $0 \mathrm{~m}$ and $30 \mathrm{~m}$ is (A) $275 \mathrm{~J}$ (B) $325 \mathrm{~J}$ (C) $400 \mathrm{~J}$ (D) $300 \mathrm{~J}$
(a) A force F = (2xi + 5yj), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x-direction from the origin to x = 5.23 m. Find the work W = F · dr done by the force on the object (in J). (b) What If? Find the work W = F · dr done by the force on the object (in J) if it moves from the origin to (5.23 m, 5.23 m) along a straight-line path making an angle of 45.0° with the positive x-axis. Is the work done by this force dependent on the path taken between the initial and final points? dependent independent
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD