Question
Calculate the mass in grams of iodine $\left(\mathrm{I}_{2}\right)$ that will react completely with $20.4 \mathrm{g}$ of aluminum (Al) to form aluminum iodide $\left(\mathrm{AlI}_{3}\right)$
Step 1
We know that the atomic mass of aluminum is 26.98 g/mol. So, we can use this to convert the mass of aluminum to moles: \[20.4 \, \text{g Al} \times \frac{1 \, \text{mol Al}}{26.98 \, \text{g Al}}\] Show more…
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Calculate the mass in grams of iodine (I2) that will react completely with 20.4 g of aluminum (Al) to form aluminum iodide (AlI3).
The vigorous reaction between aluminum and iodine gives the balanced equation: $$ 2 \mathrm{Al}(s)+3 \mathrm{I}_{2}(s) \rightarrow 2 \mathrm{AlI}_{3}(s) $$ What do the coefficicnts in this balanced chemical cquation tell us about the proportions in which these substances react on a macroscopic (mole) basis?
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