00:01
So if we're given the density of yes and we want to find the molar mass, we can use the fact that, so let's take ozone as the example, that one mole is going to weigh the molar mass.
00:18
And at standard temperature and pressure, it's going to have a volume of 22 .4 liters.
00:24
And that's proportionally equal to 2 .14 grams in every one liter.
00:32
So if you want to solve for a molar mass, you would cross multiply mm times 1, which gives you mm, is equal to 2 .14 times 22 .4.
00:57
Leaders cancels out, and then you're just going to be left with grams.
01:01
So what you're doing is you're taking the density here, and you're multiplying it by molar volume.
01:16
And that will give you the molar mass, which in the case of ozone is going to be 2 .14.
01:25
Times 22 .4, 47 .94 grams.
01:35
Let's put that up here...