00:01
Here we are calculating the malarity of some solutions, so we need to use the following equation.
00:06
We have m1, multiplied by v1 is equal to m2, multiplied by v2, so that's a molarity in the volume, respectively.
00:14
So we need to rearrange this for m2 is equal to m1, multiplied by v1, divided by v2.
00:23
So with the first example, we have m2 is equal to 0 .251 moles per litre, multiplied by 0 .125 litres.
00:39
That's all divided by 0 .375 litres.
00:44
We get an m2 value of 0 .084 molar for hcl.
00:52
So that's the first one dealt with.
00:54
We can move on to the second one...